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  1. Home/
  2. Sanjay Jagadeshwara E/
  3. Week 12 Challenge

Week 12 Challenge

Design of Foundation in STAAD Foundation 1. Isolated Footing Design isolated footing for a column 300 mm x 450 mm, carrying axial load of 1500 kN and Mu = 150 kNm using STAAD. Foundation. Assume that the moment is reversible. The safe bearing capacity of the soil is 200 kN/m2 at a depth of 1 metre from ground level. Use…

    • Sanjay Jagadeshwara E

      updated on 10 Apr 2023

    Design of Foundation in STAAD Foundation

    1. Isolated Footing

    Design isolated footing for a column 300 mm x 450 mm, carrying axial load of 1500 kN and Mu = 150 kNm using STAAD. Foundation. Assume that the moment is reversible. The safe bearing capacity of the soil is 200 kN/m2 at a depth of 1 metre from ground level. Use M 25 and Fe 415 for the footing. Also validate the design through hand calculation.

    Aim:-

            To design Isolated Footing for a column 300 mm x 450 mm carrying axial load of 1500 kN and Mu of 150kNm using STAAD Foundation. Also Validate the design through hand calculation.

    Procedure:-

    Step 1:-

    • Open STAAD Foundation Software, and Create a New General Foundation.
    • Then Setup Units as SI Unit.

            

            

            

            

    Step 2:-

    • In Main Navigator Window, select Column Position and give the coordinates as (0,0,0).

            

            

    • Click Column Dimension and give Length and Width as 0.45 and 0.3 m

            

    Step 3:-

    • Now go to Loads & Factors menu, then click Create New Load cases.
    • Then Add New Load cases of Dead Load and Live Load as Fy = -1500 kN and Mu = 150 kNm.      

             

    • Now Generate Load Combination as per Indain Standard as shown below.

            

              

            

    Step 4:-

    • Create a New Job in Job Setup menu.
    • Set Job Name as Isolated Footing and Job Type Isolated.
    • And set Design code as Indian (IS456:2000).
    • Then select all Load Cases and Create Job.

            

    Step 5:-

    • Now go to Design Parameter.
    • Click Concrete & Reinforcement, Give input as shown below.

            

            

    • Then set Cover & Soil, set Soil bearing capacity as 200 kPa.
    • And Minimum % of Contact area for Ultimate loads as 95%.

           

    • Now Footing Geametry, Set Minimum and Maximum dimensions for Footing.

            

    Step 6:-

    • Select Design option and Software will analysis and design the Footing.

            

    Result:-

    • Thus the Footing design was done successfully using STAAD Foundation.

           

           

            

    Validation of Design through Hand Calculation:-

    Footing should be symmetric with respect to column as the moment is reversible (Mx & My are same, that is square footing is to be designed.

    Service load = 1500kN

    Considering Self weight of footing & weight of backfill soil = 10% of service load

    P = 1.1 x 1500 = 1650 kN

    Pu = 1.5 x 1650 = 2475 kN

    Step 1:-

    Area Calculation:

    Area required = 1.1 x P/SBC = 1.1 x 1500 / 200 = 8.25 m2.

    Therefore L = B = √A = √8.25 = 2.87 m.

    Provide square footing of size 3.0 m x 3.0 m

    Aprovided = 9m2 > Area required which is 8.25 m2 (OK)

    Step 2:-

    Net Upward Soil Pressure:

    σ(max, min) = Pd / AProvided + Mu / Z

                    = (1.5 x 1.1 x 1500 / 9) ± (1.5 x 150 / (B × L2 / 6)     (B = L = 3 m)

                    = 275 ± 50

    σ(max) =  325 kN/m2 < 370 kN/m2 (Gross Factored Bearing capacity) ( ok) 

    σ(min) = 225 kN/m2 < 340 kN/m2

    Eccentricity (e) = M/P = 150/1500 = 0.1 m = 100 mm

     L / 6 = 3000 / 6 = 500 mm

     e < L / 6,

    Therefore, no negative soil pressure will develop hence compression steel is not required.

    Step 3:-

    Depth of Footing in the basis of Bending Moment:

    The maximum bending moment at the face of column (M)

    M = P0 × (B−b)2 / 8 = 275 × 3(3 − 0.3)2 / 8 = 751.78 kNm

    Mu = 0.138fckbd2

    751.78 × 106 = 0.138 x 20 x 3000 x d2

    d = 301 mm.

    Say d = 305 mm

    Adopt d = 600 mm due to shear consideration

    Add effective cover = 50 mm

    D = 650 mm

    Depth of footing from one way shear

    d = Pu(L−a) / 2(P + τc × L2)

       = 1.5 X 1.1 X 1500 (3 - 0.3) / 2 (1.5 x 1.1 x 1500 + 350 x 9)

       = 6682.5 / 11250 = 0.594 m = 594 mm < 600 (OK)

    Depth required for two way shear (Punching shear)

    P / L2 [L2 − (a + d)2] = 4 (a + d) d × τp

    [1.5 x 1.1 x 1500 / 9][(9 − (0.3 + 0.6)2] = 4 x 0.9 x 0.6τp

    τp = 1043.98 kN/m2 = 1.044 N/mm2

    Permissible τp = 0.25 √fck

                         = 0.25 √20

                         = 0.25 x 4.472 = 1.118 N/mm2 > 1.044 N/mm2 (OK)

    Step 4:-

    Reinforcement Calculation:

    Ast = 0.5 fck/ fy [1 − {1 − (4.6 × Mu / fckBd2)

    Ast = 5081 mm2

    p = (Ast / B×d) × 100

       = (5081 / 3000 x 650) x 100 = 0.26% > 0.12% which is min requirement, hence OK

    xu / d = 1.2 − [1.44 − 6.6 x Mu / (fck × b × d2)]1/2    

             = 1.2 − [1.44 − (6.6 x 751780 x 1000 / 20 x 3000 x 600 x 600)0.5

             = 0.0998

    Lever Arm Z = d (1 - 0.416 xu / d)

                       = 600 ( 1 - 0.416 x 0.0998)

                       = 575.089 mm

    Ast = Mu / (0.87 × fy × Z)

          = 751780 X 1000 / (0.87 X 415 X 575.089) = 3620.66 mm2

    Step 5:-

    Development Length:

    As per IS 456:2000, Clause 26.2.1.1

    σs = 415 N/mm2

    τbd for deformed bar and M20 Grade of concrete = 1.92 N/mm2

    Ld = ϕ × σA / 4τbd

        = 415 x ϕ / (4 x 1.92) = 54ϕ

        = 54 x 12 = 648 mm for 12 mm dia bar

    2. Combined Footing

    Design a combined footing using STAAD. Foundation for two columns C1, 400 mm x 400 mm carrying a service load of 800 kN and C2, 300 mm x 500 mm carrying a service load of 1200 kN. The column C1 is flushed with the property line. The columns are at 3.0 m c/c distance. The safe bearing capacity of soil is 200 kN/m2 at a depth of 1.5 m below the ground level. Use M 20 and Fe 415 for columns and footing.

    Aim:-

            To design Combined Footing for a columns C1 400 mm x 400 mm and C2 300 mm x 500 mm carrying Service load of 800 kN and 1200kN using STAAD Foundation.

    Procedure:-

    Step 1:-

    • Open STAAD Foundation Software, and Create a New General Foundation.
    • Then Setup Units as SI Unit.

            

            

            

    Step 2:-

    • In Main Navigator Window, select Column Position and give the coordinates as (0,0,0) for Column C1 and give coordinate as (3,0,0) for Column C2.

            

    Step 3:-

    • Add and assign Load of -800 kN for C1 and -1200 kN for C2.

            

    • Generate Load Combination as Indian Table as Shown brlow.

            

            

    Step 4:-

    • Next Create a New Job Setup and Name it as Combined Footing.
    • Set Job Type as Combined as shown below.
    • Then select the Column C1 and C2, click Strip footing setup and create.

            

    Step 5:-

    • Now Give Parameters for Design as shown below.

            

           

            

    Step 6:-

    • Then click Design option to Analyse the Footing.

    Result:-

    • Model and design of Combined footing was done successfully using STAAD Foundation.
    • Results are attached below.

            

            

            

     

     

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