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  1. Home/
  2. Sharukh Shaikh/
  3. Week 1 Challenge

Week 1 Challenge

1. Truss type reasoning Out of the two through type truss systems shown below, which is the most efficient in carrying gravity load? Reason it out. AIM: To find out which truss system is best for carrying out gravity load. OBSERVATION: Truss A is having vertical & inclined member forming a "N" shape & is known…

    • Sharukh Shaikh

      updated on 11 Nov 2022

    1. Truss type reasoning

    Out of the two through type truss systems shown below, which is the most efficient in carrying gravity load? Reason it out.

    AIM: To find out which truss system is best for carrying out gravity load.

    OBSERVATION: Truss A is having vertical & inclined member forming a "N" shape & is known as Pratt truss.

    •    It is the most common form of truss used
    •    compression forces is generated only in the vertical member while the inclined member only take tension.
    •    Pratt truss have more unloaded member as compared to the howe truss.             

                            Truss B is opposite of pratt truss & is known as howe truss

    •   Compression forces is generated in inclined members while vertical member takes the tension
    •   The structure generates less 0 force member as compared to Pratt truss

     

     CONCLUSION: As Pratt truss distributes loads more evenly and has more 0 force member as compared to Howe

                           truss we can clearly say that TRUSS A is more efficient in carrying Gravity load as compared to 

                           TRUSS B.         

    -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

    2. Deflection shape & Bending Moment Drawing (Qualitative approach)

    For the beam & Frame below draw deflected shape and bending moment drawing. (Qualitative approach). E & I are constants.

    --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

    3. Determine MOI, Weight, C/S area of sections below

    A) 

     

    MOI ALONG  Ixx=18360000 mm4

    MOI ALONG  Iyy=1987000 mm4

    Cross sec area=3040mm2

    Weight per meter= 23.8kg/m

    -----------------------------------------

    --------------------------------------------

    B)

    MOI ALONG  Ixx=5470000000 mm4

    MOI ALONG  Iyy=135000000 mm4

    Cross sec area=26000mm2

    Weight per meter= 204.1kg/m

    -----------------------------------------

    --------------------------------------------

    C)

    MOI ALONG  Ixx=185000000 mm4

    MOI ALONG  Iyy=14200000 mm4

    Cross sec area=9651mm2

    Weight per meter= 75.8kg/m

    -----------------------------------------

    --------------------------------------------

    D)

    MOI ALONG  Ixx=671000000 mm4

    MOI ALONG  Iyy=89800000 mm4

    Cross sec area=1677.4mm2

    Weight per meter= 132kg/m

    ( Calculation sheet for above is attached)

    ------------------------------------------------------------------------------------------------

    ------------------------------------------------------------------------------------------------

    ----------------------------------------------

     

    4. Load calculation problem

    For the floor framing below, Calculate the load on interior beam, Exterior beam, Interior Girder and exterior girder having Floor Load of 10kN/m2 

    Soln:  Interior beam=20KN/m(-)

              Enterior beam=10KN/m(-)

              Interior Girder=22.5KN/m(-)

              Enterior Girder=20KN/m(-)

    ( Calculation sheet for above is attached)

    ------------------------------------------------------------------------------------------------

    ------------------------------------------------------------------------------------------------

    ----------------------------------------------

    5. Expansion joint size determination for temperature stated problem

    Assuming a bridge, made of steel, with an initial total length of 2000 m at -20 ºC, calculate the length difference at 40 ºC and its total length.

    Coefficient of Thermal expansion of steel = 12x10-6/°C

    Soln: Length of Bridge at-20 ºC =2000m,

             Coefficient of Thermal expansion of steel = 12x10-6/°C

             we know that Length difference at 40ºC= 2000 x 40 x 12x10-6 

                                                                                     = 0.96m

                            Hence the length differene at  40 ºC =0.96m

    ------------------------------------------------------------------------------------------------------------------------------

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      Week 12 Challenge

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