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  1. Home/
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  3. Section Modulus calculation and optimization

Section Modulus calculation and optimization

  SECTION MODULUS Section modulus is a property used to describe the bending strength of a structural component, such as a car hood. It measures the resistance of a material to bending or deformation. In the case of a car hood, the section modulus is determined by the shape and size of the cross-section of the hood.…

    • IVIN TROY

      updated on 01 Apr 2023

     

    SECTION MODULUS

    Section modulus is a property used to describe the bending strength of a structural component, such as a car hood. It measures the resistance of a material to bending or deformation.

    In the case of a car hood, the section modulus is determined by the shape and size of the cross-section of the hood. The greater the section modulus, the greater the bending strength of the hood.

    To calculate the section modulus of a car hood, you need to know the moment of inertia and the distance from the neutral axis of the cross-section to the outermost edge of the hood.

     The moment of inertia is a measure of the distribution of mass around the cross-sectional area of the hood, and it is calculated based on the shape and size of the cross-section.

    The section modulus is calculated by dividing the moment of inertia by the distance from the neutral axis to the outermost edge of the hood.

     Higher section modulus means the hood will be less likely to bend or deform under load, which is important for ensuring the safety and longevity of the car.

     

    The equation for section modulus is

    S = I / Y

    where S is the section modulus   I is  the moment of inertia of the cross-sectional area, and Y is the distance from the neutral axis to the most extreme point in the section.

    The moment of inertia is a measure of the distribution of the area around the neutral axis.

     The neutral axis is the axis where there is no bending or flexing of the section.

    The moment of inertia is calculated by integrating the cross-sectional area around the neutral axis.

    The distance Y is the distance from the neutral axis to the most extreme point in the section. This is the point where the bending or flexing of the section is maximum.

    The section modulus is an important parameter in engineering design, as it determines the strength and stiffness of a structural member. In the case of a car hood, a higher section modulus means that it is stronger and less likely to deform or buckle under a load.

    By calculating the section modulus of a car hood, engineers can determine its ability to resist bending and flexing under different loads, which is important for ensuring the safety and durability of the hood.

     

    In NX CAD, you can calculate the section modulus of a cross-section using the following steps:

    • Create a 2D sketch of the cross-section of the beam or structural member in the modelling environment of NX CAD.
    • Calculate the moment of inertia by possible minimum thickness of of the outer panel and inner panel.It is done by trimming the bottom line of upperpanel and top line of inner panel.
    • It is taken as case 1 and run the section inertia analysis command and the maximum and minimum value is noted .The minimum value of section modulus is considered because we have to consider the worse conditions.
    • The distance from the refernce line to the end of the object is found.
    • The section modulus is found by applying in equation.
    • The second case Case 2 is  found by offsetting the innerpanel by 0.5mm downwards to get a more cross section area.
    • The same procedure is followed and applied in the equation.
    • The minimum value of moment of inertia is noted .
    • The section modulus is found by applying in the equation S=I/Y.

     

                                                                             CASE 1

     

     

    From the figure we get the following datas,

     

     

     

     

    Moment of inertia (minimum value)  I =1.6099x10^4 mm^4

    Distance from reference line  Y = 440.85 mm

    We know  Section modulus   S= I/Y

    Therefore

     Section modulus  S = 1.6099x10^4 mm^4  / 440.85 mm

    So     S= 36.51 mm^3

     

                                              CASE 2

     

    From the figure we get the following datas,

     

     

     

    Moment of inertia (minimum value)  I =2.3829x10^4 mm^4

    Distance from reference line  Y = 440.85 mm

    We know  Section modulus  S= I/Y

    Therefore

    S = 2.3829x10^4 mm^4  /  440.85 mm

    So     S= 64.25 mm^3

    Therefore it is fondout that if the crosssection is increased the section modulus is also increased.

     

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